2u^2+4u+19=(U+4)^2

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Solution for 2u^2+4u+19=(U+4)^2 equation: 



2u^2+4u+19=(+4)^2

We move all terms to the left:

2u^2+4u+19-((+4)^2)=0

We add all the numbers together, and all the variables

2u^2+4u+19-(4^2)=0

We add all the numbers together, and all the variables

2u^2+4u+3=0

a = 2; b = 4; c = +3;
Δ = b2-4ac
Δ = 42-4·2·3
Δ = -8
Delta is less than zero, so there is no solution for the equation

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